(6x^3-5x^2-4x+3)/(x-1)

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Solution for (6x^3-5x^2-4x+3)/(x-1) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(6*x^3-(5*x^2)-(4*x)+3)/(x-1) = 0

(6*x^3-5*x^2-4*x+3)/(x-1) = 0

6*x^3-5*x^2-4*x+3 = 0

6*x^3-5*x^2-4*x+3 = 0

{ 1, -1, 3, -3 }

1

x = 1

6*x^3-5*x^2-4*x+3 = 0

1

x-1

6*x^2+x-3

6*x^3-5*x^2-4*x+3

x-1

6*x^2-6*x^3

x^2-4*x+3

x-x^2

3-3*x

3*x-3

0

6*x^2+x-3 = 0

DELTA = 1^2-(-3*4*6)

DELTA = 73

DELTA > 0

x = (73^(1/2)-1)/(2*6) or x = (-73^(1/2)-1)/(2*6)

x = (73^(1/2)-1)/12 or x = (-(73^(1/2)+1))/12

x in { (-(73^(1/2)+1))/12, (73^(1/2)-1)/12, 1} 

(x+(73^(1/2)+1)/12)*(x-((73^(1/2)-1)/12))*(x-1) = 0

(x+(73^(1/2)+1)/12)*(x-((73^(1/2)-1)/12)) = 0

( x+(73^(1/2)+1)/12 )

x+(73^(1/2)+1)/12 = 0 // - (73^(1/2)+1)/12

x = -((73^(1/2)+1)/12)

( x-((73^(1/2)-1)/12) )

x-((73^(1/2)-1)/12) = 0 // + (73^(1/2)-1)/12

x = (73^(1/2)-1)/12

x in { -((73^(1/2)+1)/12), (73^(1/2)-1)/12 }

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